Capacitance with a Metal (conducting) Slab - Physics Class 12
Capacitance with a Metal (conducting) Slab—
Let we have a capacitor of plate area ‘A’ and separation ‘d’ between the plates, then
Now, we place a metal slab of thickness ‘t’ in between the two plates of capacitor and the electric field in the conducting slab is zero. Hence, the potential difference between the plates is,